Find the least number of 4 digits which is divisible by 20 25 30
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LCM of 20 ,25 and 30 =300
Smallest 4 digit no. =1000
1000÷ 300 leaves the remainder 100
300 - 100 = 200
1000+200= 1200
Therefore, 1200 is the smallest 4 digit number divisible by 20 , 25 and 30
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