find the least number of 6 digit from which if 26 is subtracted yhe resultant number is exactly divisible 16,20,24 and 36
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Step-by-step explanation:
first calculate the lcm of 16,24 and 36
the lcm of 16,24 and 36 is 144
now, 144 is the least number which is exactly divided by 16,24 and 36
next, add 26
144+26=170
so 170 is the least number from which 26 is subtracted, the result is exactly divisible by 16, 24,36
verification: 170-26=144/24=6
144/16=9
144/36=4
the remainder is zero in each case
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