Question

Find the least number of five digits exactly divisible by 15, 24 and 30

Answer 1

find LCM of 15,24,30

LCM= 120

divide the smallest 5 digit no by 120

10000/120

remainder= 40

for it to be exactly divisible by 120

remainder= 40+80

divident= 10000+80

            = 10080

the largest 5 digit number that divides 15,24 and 30 is 10080