Question

find the least number of five digits exactly divisible by 32,36,40,45

Answer 1

The LCM of 32, 36, 40 and 45 is 360.
Smallest 5- digit no.= 10000
(Divide 10000 by 360)
The remainder is 280.
Req. no.=10000+( Divisor - Remainder)
             = 10000+( 360- 280)
             = 10000+( 80)
             = 10080
Ans.= 10080 is the least no. of 5 - digits which is exactly divisible by 32, 36, 40 and 45.