Find the least number of five digits which is exactly divisible by 32,36 and 45 (with full solution)
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LCM of 32,36 and 45 =1440
Smallest 5 - digit no. =10000
Divide 10000 by 1440
Remainder = 1360
Req. no.=10000+(1440-1360)
=10000+80
=10080
Ans.=10800 is the smallest 5- digit no. exactly divisible by 32,36 and 45.
Smallest 5 - digit no. =10000
Divide 10000 by 1440
Remainder = 1360
Req. no.=10000+(1440-1360)
=10000+80
=10080
Ans.=10800 is the smallest 5- digit no. exactly divisible by 32,36 and 45.
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