Question

Find the least number of five digits which is exactly divisible by 32,36,40,45,48

Answer 1

A number which is divisible by 32,36,40,45,48 must also be divisible my their LCM.

So, we find the LCM of 32,36,40,45,48

$32 = 2 {}^{5} \\ 36 = 2 {}^{2} \times 3 { }^{2} \\ 40 = 2 {}^{3} \times 5 \\ 45 = 3 {}^{2} \times 5 \\ 48 = 2 {}^{4} \times 3$
$so \: LCM \: = 2 {}^{5} \times 3 { }^{2} \times 5 = 1440$
=>Now we need to find the smallest five digit number divisible by 1440.

The smallest five digit number is 10000.

10000 = 6×1440 +1360

That is, on dividing 10000 by 1440 quotient is 6

So, (7×1440) is the smallest required five-digit number

ANSWER: [ 7×1440 = 10080]

Answer 2

Answer:

that is correct answer