Find the least number of five digits which is exactly divisible by 32,36,40,45 and 48
Answers
Answered by
3
Answer:
10080
Step-by-step explanation:
Prime factorize
32=2×2×2×2×2=2∧5
36=3×3×2×2=3²×2²
40=5×2×2×2=5×2³
45=5×3²
48=3×2×2×2×2=3×2∧4
LCM=2∧5×3²×5
=1440
Smallest 5 digit number=10000
Remainder is 1360
Req. no.=10000+(1440-1360)
=10000+80
=10080
Answered by
6
Answer:
10320
Step-by-step explanation:
first find the LCM of 32,36,40,45,48
therefore the LCM is 1440
the remainder is 120
so 10000+(1440-120)
10000+1320
10320
I think it will be helpful
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