Question

Find the least number of five digits which is exactly divisible by 32,36,40,45 and 48​

Answer 1

Answer:

10080

Step-by-step explanation:

Prime factorize

32=2×2×2×2×2=2∧5

36=3×3×2×2=3²×2²

40=5×2×2×2=5×2³

45=5×3²

48=3×2×2×2×2=3×2∧4

LCM=2∧5×3²×5

       =1440

Smallest 5 digit number=10000

Remainder is 1360

Req. no.=10000+(1440-1360)

             =10000+80

             =10080

Answer 2

Answer:

10320

Step-by-step explanation:

first find the LCM of 32,36,40,45,48

therefore the LCM is 1440

the remainder is 120

so 10000+(1440-120)

10000+1320

10320

I think it will be helpful