Question

find the least number of four digits that is a perfect square with full solution please write a full solution ​

Answer 1

Step-by-step explanation:

The smallest four digit no. = 1000

32^2 is more than 1000 by 24;

So the least number to be added to 1000 is 24.

Therefore, 1000+24 = 1024 is the smallest four digit number which is a perfect square.

Hope u get it.

Answer 2

Step-by-step explanation:

$We \: know \: that-$

$least \: 4 \: digit \: no.=1000$

$(961 < 1000 < 1024)$

$(31² < 1000 < 32²)$

$We \: have \: to \: find \: 4 \: digit \: no.$

$So ,1024 \: is \: the \: least \: 4 \: digit \: no-$

$which \: is \: a \: perfect \: square \: of \: 32$