Find the least number of four digits
which on dividing by 10 and 12 leaves a
remainder of 7 in each case.
Answers
Answered by
7
Answer : 1027 ✔✔
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Solution :
As we know that :
Least number of 4 digit = 1000
Now, L. C. M. of 10 and 12 = 60
60 ) 1000 ( 16
- 60
________
400
- 360
________
40
Now, 1000 + (60-40) = 1020
1020 is the 4 digit least number which can be divided by 10 and 12.
Now, we have to find a least number of 4 digit leaves a remainder of 7 after dividing by 10 and 12 each case.
1020 + 7 = 1027
10 ) 1027 (102
-10
__________
027
-20
__________
7
12 ) 1027 ( 85
-96
__________
67
-60
__________
7
So, the number will be 1027 ✔
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I hope it will help you ☺
Fóllòw Më ❤
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