find the least number of square tiles required to pave the ceiling of a room 15m 17cm long and 9m 2cm broad
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Step-by-step explanation:
Lenght of the room=15m 17cm=
15×100+17=1517
breadth=9m2cm=902 cm
the HCF of the 1517 and 902 will be size of saure tiles
HCF 1517 and 902 = 41cm
area of room= leanth×breadth=1517×902cm²
area of tiles=41×41cm²1
so num. of tiles required(1517×902)(41×41)
=814 tiles
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