Question

Find the least number that can be added to 3000 so that it should be exactly divisible to 45

Answer 1

Answer:

15

Step-by-step explanation:

1. first take out the L.C.M. of 3000

2.you will be left over with 3 and 5

3.multiply both i.e. 3*5 = 15

4.when you add 15 with 3000 you will get 3015

5.when you divide 3015 with 45 you will get 67.

And now , the number is exactly divisible by 45