Math, asked by bansalvarun889, 1 year ago

Find the least number that is divisible by 15 18 20 24 leaving remainder 12 in each case

Answers

Answered by Panzer786
6
Heya !!!


15 - 12 = 3

18 -12 = 6

20 -12 = 8

24 -12 = 12

Prime factorisation of 3 = 1 × 3

Prime factorisation of 6 = 2 × 3


Prime factorisation of 8 = 2 × 2 × 2


Prime factorisation of 12 = 2 × 2 × 3



LCM of 3 , 6 , 8 , 12 = 24


Hence,


Required Number =24 .



HOPE IT WILL HELP YOU...... :-)
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