Question

Find the least number that is divisible by all the
What is the smallest number that, when divided by 35, 56 and 91 leaves remainders of 7 in
each case?
​

Answer 1

Step-by-step explanation:

if a number x divided by 35,56 and 91 leaves 7 as remainder in each case then

then x - 7 is the LCM of 35,56 and 91

LCM of 35,56 and 91 is 3640

x - 7 = 3640

x = 3640 + 7

x = 3647

the answer for this question is 3647

Answer 2

Answer:

To find out the smallest number which on dividing leaves remainder 7 , we need to subtract 35,56,91 from 7

35 - 7 = 28

56 - 7= 49

91 - 7= 84

Now,

we need to do the LCM of 28,49,84

7 | 28, 49, 84

2| 4, 7, 12

2 | 2, 7 , 6

| 1 , 7 , 3

therefore, LCM = 7×2×2×7×3 = 588

ans) Thus, 588 is the smallest number which on dividing with 35,56,91 leaves remainder 7