Question

Find the least number that is exactly divisible by 12, 30 and 66 without leaving a remainder.​

Answer 1

Answer:

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.Nov 22, 2019

Step-by-step explanation:

First, factor the numbers into primes:

66 = 2 x 3 x 11; 99 = 3 x 3 x 11; 88 = 2 x 2 x 2 x 11

Common factors are 2 x 2; 3 x 3; and 11; so 2 x 2 x 2 x 3 x 3 x 11 or 792 is the smallest number divisible by 66; 99; and 88.

Add 6 to 792, gives 798, divisible by is 66 99 88