Question

find the least number that must be added to 1246 so that the result will be a perfect square
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Answer 1

answer Is 590 that is too simple

Answer 2

Step-by-step explanation:

$\color{darkred}\huge\bold\star\underline\mathcal{Solution\: :-}\star \\ \\ \sqrt{1225} = 35 \\ 1225 < 1246 \\ \\ {36}^{2} \\ = 36 \times 36 \\ = {6}^{2} \times {6}^{2} \\ = {6}^{4} \\ = 1296 \\ \\ ∴ \: \: the \: \: least \: \: number \: \: that \: \: must \: \: be \\ added \: \: to \: \: 1246 \: \: so \: \: that \: \: the \\ result \: \: will \: \: be \: \: a \: \: perfect \: \: square \: \: : \\ 1296 - 1246 \\ = \boxed { \bold{\underline{ \underline{50}}}}$