Math, asked by hebazareen46, 8 hours ago

Find the least number that must be added to 6412 so as to get a perfect square. Also find the square root of the perfect square.​

Answers

Answered by sivapriya71
1

The least no. which must be added to 6412 to

make it a perfect square is 149(6561-6412)

-6412+149-6561

therefore, square root of 6561- 81

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Answered by brainlysrijanuknown2
7

Answer:

Complete step by step answer:

We are given a number 64126412.

Therefore, 6561−6412=1496561−6412=149

Hence, 149149 is the least number which must be added to 64126412 so as to get a perfect square.

The required number is 6412+149=65616412+149=6561.

Now we evaluate the square root of the number 65616561.

On factorisation, we get

6561−−−−√=3×3×3×3×3×3×3×3−−−−−−−−−−−−−−−−−−−−−−−√6561=3×3×3×3×3×3×3×3

Evaluate the square root. The numbers which are in the pair will come out from the square root.

That is,

6561−−−−√=3×3×3×3

6561=3×3×3×3

⇒6561−−−−√=81

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