Find the least number that must be added to 6412 so as to get a perfect square. Also find the square root of the perfect square.
Answers
Answered by
1
The least no. which must be added to 6412 to
make it a perfect square is 149(6561-6412)
-6412+149-6561
therefore, square root of 6561- 81
Hope it helps if you like the answer then please
mark it brainliest
Answered by
7
Answer:
Complete step by step answer:
We are given a number 64126412.
Therefore, 6561−6412=1496561−6412=149
Hence, 149149 is the least number which must be added to 64126412 so as to get a perfect square.
The required number is 6412+149=65616412+149=6561.
Now we evaluate the square root of the number 65616561.
On factorisation, we get
6561−−−−√=3×3×3×3×3×3×3×3−−−−−−−−−−−−−−−−−−−−−−−√6561=3×3×3×3×3×3×3×3
Evaluate the square root. The numbers which are in the pair will come out from the square root.
That is,
6561−−−−√=3×3×3×3
6561=3×3×3×3
⇒6561−−−−√=81
Similar questions