Question

find the least number that when divided by 16,18,20 leaves a remainder 4 in each case but completely divisible by 7​

Answer 1

Answer:

first find the LCM OF 16, 18 AND 20 By prime factorization

multiples of 20 -----20, 40, 60 , 80, 100, 120 140, .......720

lcm is 720

but when we add 4 the no. 724 which is not divisible by 7

720 * 4 + 4 = 2884

now this no. is divisible by 16 ,18 and 20 leaves remainder 4 and completely divisible by 7

answer 2884