find the least number that will divided by 9,11,13 gives remainder 1,2,3.
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Answered by
0
Answer:
Answer is 360 first subtract 1from 9,2from 11 ,and 3 from 13 then find LCM of 8,9,10
Answered by
20
Answer:
we have to find least number which is divisible by 9,11 , 13 and also leaves remainder 1,2,3 ...
Now, your solution
let the smallest no be x
x / 9 = 1 remainder
x / 11 = 2 remainder
x / 13 = 3 remainder
both side multiply by 2
2x / 9 = remainder 2
2x / 11 = remainder 4
2x / 13 = remainder 6
now you noticed that if we add 7 to 2x so all numbers are fully divisible.
2x + 7/9 = 0 ( remainder)
2x + 7 / 11 = 0 ( remainder)
2x + 7/ 13 = 0 ( remainder)
this shows that 2x + 7 is completely divisible by 9 , 11 , 13
now multiply 9 * 11 * 13 = 1287
2x + 7 = 1287
2x = 1287 - 7 = 1280
x = 1280 / 2= 640
so 640 is the least number which is divisible by 9,11,13 and leaves remainder 1, 2, 3
I hope my answer is helpful for you ✌✌
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