Question

find the least number which devided by 21,28 and 36 leaves rimander 2 in each case​

Answer 1

Answer:

Step-by-step explanation:

First find the LCM of 21, 28 and 36

Prime factorising the 3 numbers we get

21 = 3 × 7

28 = 2×2×7 = 2^2 × 7

36 = 2×2×3×3 = 2^2 × 3^2

LCM = product of highest power of each prime factor

LCM = 3^2 × 2^2 ×7

= 252

Since we need to find the number which when divided by 22, 28 and 36 leaving the reminder 2

Hence required number is 252+2

= 254

And 254