find the least number which is a perfect square and which is also divisible by 16, 18 and 45. plz answer fast I will mark u as brainliest.
Answers
Answered by
17
the least no. which is divisible by 16,18,45 is the L.C.M. of 16,18,and 45 which is 2×2×2×2×3×3×5
making pairs,(2×2)×(2×2)×(3×3)×5
we find that 5 remains unpaired
hence it should be multiplied by 5 to make it a perfect square
hence the least no. that is a perfect sq. and also divisible by 16,18 and 45 is
(2×2)×(2×2)×(3×3)×(5×5) that is 3600
making pairs,(2×2)×(2×2)×(3×3)×5
we find that 5 remains unpaired
hence it should be multiplied by 5 to make it a perfect square
hence the least no. that is a perfect sq. and also divisible by 16,18 and 45 is
(2×2)×(2×2)×(3×3)×(5×5) that is 3600
Answered by
47
In order to find the least number, we need to do the LCM of 16,18 and 45.
Prime factorization of 16 = 2^4
Prime factorization of 18 = 2 * 3 * 3
Prime factorization of 45 = 3 * 3 * 5
LCM(16,18,45) = 2^4 * 3^2 * 5
= 720.
As we can see here, 5 is not in pair. So, we need to multiply 720 by 5 to make it a perfect square.
= > 720 * 5
= > 3600.
Therefore, the least perfect square number = 3600.
Hope this helps!
siddhartharao77:
:-)
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