Find the least number which is exactly divisible by 12 20 36 leaving reminder 8
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let the hcf of two nos be X
we know
lcm \times hcf = \: product \: two \: numberslcm×hcf=producttwonumbers
\begin{lgathered}180 \times \: x = 2160 \\ x = \frac{2160}{180} \\ x = 2\end{lgathered}180×x=2160x=1802160x=2
12)
\begin{lgathered}36 - 8 = 28 \\ 20 - 8 = 12 \\ 12 - 8 = 4 \\\end{lgathered}36−8=2820−8=1212−8=4
so we have to find the lcm of 28 12 and 4
\begin{lgathered}28 = 7 \times 4 \\ 12 = 3 \times 4 \\ 4 = 1 \times 4\end{lgathered}28=7×412=3×44=1×4
thus 4 being the hcf will be taken out and multiplied with rest of the nos
\begin{lgathered}lcm = 4 \times 7 \times 3 \\ lcm = 84\end{lgathered}lcm=4×7×3lcm=84
hope so it helps
za6715:
Thanks.
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the number which is divisible by 12 20 36 is 2
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