Question

Find the least number which is exactly divisible by 32 36 45 60 80

Answer 1

Answer:

1440

Step-by-step explanation:

Step 1 : Find the prime factors of the given numbers

32 = 2 * 2 * 2 * 2 * 2

36 = 2 * 3 * 2 * 3

45 = 3 * 3 * 5

60 = 3 * 5 * 2 * 2

80 = 5 * 2 * 2 * 2 * 2

Step 2 : Find the LCM of the numbers

LCM = 1440

∴ The least number which is exactly divisible by 32, 36, 45, 60, 80 is 1440

Check :-

1) $\dfrac{1440}{32}$ = 45

2) $\dfrac{1400}{36}$ = 40

3) $\dfrac{1440}{45}$ = 32

4) $\dfrac{1440}{60}$ = 24

5) $\dfrac{1440}{80}$ = 18

In the above cases, the LCM i.e. 1440 is divisible by the given numbers i.e. 32, 36, 45, 60 and 80. No remainder is left while dividing.

Answer 2

Answer:


1440


Step-by-step explanation:


Step 1 : Find the prime factors of the given numbers


32 = 2 * 2 * 2 * 2 * 2


36 = 2 * 3 * 2 * 3


45 = 3 * 3 * 5


60 = 3 * 5 * 2 * 2


80 = 5 * 2 * 2 * 2 * 2



Step 2 : Find the LCM of the numbers


LCM = 1440



∴ The least number which is exactly divisible by 32, 36, 45, 60, 80 is 1440