find the least number which is exactly divisible by each one of the number 12,16 and 24
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First we have to find the L.C.M of 12,16,24,36
L.C.M by prime factorization method
12= 2*2*3
16=2*2*2*2
24= 2*2*2*3
36= 2*2*3*3
L.C.M= 2*2*2*2*3*3 = 144
Add remainder 7 to the L.C.M = 144+7= 151
The least number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case IS 151
L.C.M by prime factorization method
12= 2*2*3
16=2*2*2*2
24= 2*2*2*3
36= 2*2*3*3
L.C.M= 2*2*2*2*3*3 = 144
Add remainder 7 to the L.C.M = 144+7= 151
The least number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case IS 151
gujjarritik008:
Why 36
Answered by
1
2 is ur answer my dear friend you should do this by the HCF method highest common factor
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