Question

Find the least number which leaves a remainder 9 when divided by 18, 24 and 15​

Answer 1

Answer:

We find the LCM of 8, 9, 12 and 15. In each case it leaves a remainder 1 so we add 1 in the LCM of the numbers. i.e. 360+1=361. Therefore, the least number which when divided by 8, 9, 12 and 15 leaves a remainder of one in each case is 361

Answer 2

Least number agr find krna ho to hme LCM dena pdta h

Agr question khta h leaves remainder to apko jo numbers h na unme se aur jo no. leave krne ke liye kh rhe h usme se subtract kr do

For eg:- 18-9= 9

24-9=13

15-9=4

Now we will Give the LCM of 9,13,4 ,

I will do LCM in upper page u can see it, Now I will multiply of those numbers,

2×2×3×13= 156

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