Find the least number which must be added to 1750 so obtained aperfect squar
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Find the least number which must be added to 1750 to make it a perfect square .
for this we find
[tex] \sqrt{1750} [/tex
then , it's value is 41.833
So, in this case we remove the decimal i.e. .833
so we have 41 now.
we add 1 to this thing.
41+1=42
Let's find 42×42
That is 1764
Now subtracting 1750 from 1764 gives us 14.
that's it.
we need to add 14 to make it a perfect square
for this we find
[tex] \sqrt{1750} [/tex
then , it's value is 41.833
So, in this case we remove the decimal i.e. .833
so we have 41 now.
we add 1 to this thing.
41+1=42
Let's find 42×42
That is 1764
Now subtracting 1750 from 1764 gives us 14.
that's it.
we need to add 14 to make it a perfect square
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