Math, asked by harshitha59, 1 year ago

Find the least number which must be subtracted from 2361 to make it a perfect square.Find the perfect square and also its square root.

Answers

Answered by adarsh275

57 i.e. 2361-57=2304=48×48=square of 48

harshitha59: Y did u subtract 57 from 2316

adarsh275: to make it perfect square

harshitha59: How did u get 57

adarsh275: listen square of 5o is 2500 and squre of 48 is 2304 hence 2361 lie in bw them and also square of 49 is 2401

Answered by wifilethbridge

Answer:

Given : Number = 2361

To Find: Find the least number which must be subtracted from 2361 to make it a perfect square.Find the perfect square and also its square root.

Solution:

Number = 2361

So, $\sqrt{2361}=48.590$

So, the perfect square is 48 .

So, $48^2=2304$

So, The nearest perfect square is 2304

So, the least number which must be subtracted from 2361 to make it a perfect square = 2361-2304=57

So, The perfect square = $48^2=2304$

Square root = $\sqrt{2304}=48$

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