Question

find the least number which must be subtracted from 6203 to obtain a perfect square. Also find square root of the number so obtained. ​

Answer 1

⇒$\:119\: is\:the\: smallest \:number\:which\:must \:be$

$\:subtracted \:to \:get \:a\: perfect\: square.\:$

⇒$\:Hence,\:6203\:−\:119\:=\:1184\: is \:the\: perfect\: square.\:$

⇒$\:Therefore, \:the \:square \:root \: of\: 1184\:is \:78.\:$

Answer 2

Step-by-step explanation:

Solution :

To find the least number that must be subtracted from 6203 to obtain a perfect square , we will have to compute the square root of 6203 by Long division method.

78

____________

| 6203

| 49

| ____________ 148 | 1303

8 | 1184

| ____________

| 119

|

So the reminder is 119 and 119 is the least number that must be subtracted from 6203 to get a perfect square.

Now we will subtract 119 from 6203

6203 - 119 = 6084

Square root of 6084 by long division.

78

_____________

7 | 6084

| 49

| _____________

148 | 1184

8 | 1184

| _____________

| 0

|______________

→ √6084 = 78

Answer

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