Math, asked by gokusupersain3990, 1 year ago

Find the least number which must be subtracted from the 61510 number to make perfect square

Answers

Answered by Anonymous
3
61510 - 61009 = 491 as 61009 is perfect sqaure of 247
Answered by Wafabhatt
10

Answer:

To find the least number which must be subtracted from the 61510 number to make a perfect squared number, we've to take the square root of 61510 which gives us the value equal to 248.012. So we'll judge that the smallest nearest squared number to 61510 will be 248. So we'll perform the following calculations;

(248)² = 61504 < 61510

Now we can achieve the least number which must be subtracted from 61510 to make it a perfect squared number, which is;

61510 - 61504 = 6

Now we can conclude that 6 is the least number that must be subtracted from 61510 to make it a perfect squared number.

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