Math, asked by afsha74, 11 months ago

Find the least number which on dividing by 15,20 and 40 leaves the remainder 9​

Answers

Answered by geniusstar1
5

Answer:

the no which is divided by 15,20,40 is 129

Answered by CosmicBeing123
6

Answer:

129

Step-by-step explanation:

Least no. = LCM of 15 , 20 and 40

LCM=120

Remainder should be 9 , so add 9 to the LCM.

120+9 =129

VERIFICATION: 129/15=8 , remainder 9

129/20=6 , remainder 9

129/40=3 , remainder 9

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