Find the least number which should be added to 10000 so that the sum is exactly divisible by 129
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Answered by
31
First divide 10000 by 129 and get the remainder. Then add the remainder to 10000 and u will get ur answer.. Hope it helps u.
Answered by
22
10000+(-67) =9933
9933÷128 =77
or 9933+129 =10062
10062÷129=78
9933÷128 =77
or 9933+129 =10062
10062÷129=78
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