find the least number which when devide by 12,15,20 and 24 leave a remainder 2 in each case
Answers
Answered by
0
Answer:
122
Step-by-step explanation:
LCM OF (12, 15, 20, 24)=120
So, required number is 122 which when divided by 12,15,20 and 24 leave a remainder 2 in each case
Similar questions