Math, asked by hrrsanjaygupta84, 1 year ago

find the least number which when divided by 10, 12, 16 and 24 leaves remainder 9 in each case

Answers

Answered by divyanshu85
3
L. C. M of the no. is 240
Then
=240+9
=249
Answered by raunit16
2
10 = 2×5
12 = 2×2×3
16 = 2×2×2×2
24 = 2×2×2×3

LCM = 2×2×2×2×3×5 = 240

Let,
Dividend be 'X'

X = 240 - 9
= 231 Ans.
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