Find the least number which when divided by 12,16,18,21 and 28 leaves the reminder 7 in each case
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Answered by
0
Answer:
the answer maybe different but the answer are
Step-by-step explanation:
- 5
- 9
- 12
- 14
- 21
Answered by
5
the no. which divided by these no is =
lcm of these no.
and the requied no. is. = lcm+7
so,
12=2*2*3
16=2*2*2*2
18=2*3*3
21=3*7
28=2*2*7
lcm=2*2*2*2*3*3*7
lcm=16*9*7
lcm=1008
the reqired no. is = lcm+7
=1008+7
=1015
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