Find the least number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case.
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Answered by
481
First we have to find the L.C.M of 12,16,24,36
L.C.M by prime factorization method
12= 2*2*3
16=2*2*2*2
24= 2*2*2*3
36= 2*2*3*3
L.C.M= 2*2*2*2*3*3 = 144
Add remainder 7 to the L.C.M = 144+7= 151
The least number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case IS 151
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Hope this will help you......
L.C.M by prime factorization method
12= 2*2*3
16=2*2*2*2
24= 2*2*2*3
36= 2*2*3*3
L.C.M= 2*2*2*2*3*3 = 144
Add remainder 7 to the L.C.M = 144+7= 151
The least number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case IS 151
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Hope this will help you......
Answered by
61
Answer:
Step-by-step explanation:
Secondary SchoolMath 8+4 pts
Find the least number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case.
Report by Anjlishasree 18.07.2016
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nikitasingh79
Nikitasingh79 ★ Brainly Teacher ★
First we have to find the L.C.M of 12,16,24,36
L.C.M by prime factorization method
12= 2*2*3
16=2*2*2*2
24= 2*2*2*3
36= 2*2*3*3
L.C.M= 2*2*2*2*3*3 = 144
Add remainder 7 to the L.C.M = 144+7= 151
The least number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case IS 151
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