find the least number which when divided by 12 16 and 18 will leave in each case the same remainder 5
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Answer:
144 is the smallest number divisible by 12, 16 and 18. But our number should be the least and should give 5 as the remainder. Hence, The least number when divided by 12, 16, and 18, gives a remainder of 5 is 149.
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Factor of 12=2×2×3
Factor of 16=2×2×2×2
Factor of 18=2×3×3
∴ L.C.M of 12,16,18 is 144.
Hence, the required number =144+5=149.
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