Question

find the least number which when divided by 14 42 and 28 leave remainder 3 in each case ​

Answer 1

$Given \: numbers \: 14, 42 \: and \: 28$

Finding the L.C.M of 14,42 and 28 :

2 | 14,42, 28

___________

7 | 7 , 21, 14

___________

*** 1 , 3 , 2

$L.C.M ( 14,42, 28 ) \\= 2\times 7 \times 1 \times 3\times 2 \\= 84$

$Now, \red{ The \: least \: number \: which }\\\red{ when \: divided \: 14, 42 \: and \: 28 \: leave}\\\red{ remainder \: 3 \: in \: each \: case } \\\green { = LCM ( 14,42, 28 ) + Remainder } \\= 84 + 3 \\\green { = 87 }$

Therefore.,

$\red{ Required \: least \: number }\green { = 87}$

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Answer 2

Answer:

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