Find the least number which when divided by 16, 28 and 40 leaves a
remainder 7 in each case.Step by step
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0
Answer:
The least number which when divided by 16,28,40 and 77 leaves 5 as a remainder in each case is 6165.
Answered by
0
Answer:
567
Step-by-step explanation:
in such such type of question you first find the LCM of all the given no. then add the remainder to the lcm.
We have to find LCM because we need the least no. divisible by all of them
LCM (16,28,40)=560
least no.= LCM +remainder
=560+7
=567
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