Question

find the least number which when divided by 18 , 28 , 32 and 42 leaves a remainder 5 in each case.
thanks for answering will mark as brainliest answer

Answer 1

Answer:

please mark as brainlist answer!!

Step-by-step explanation:

the smallest number which when divided by 18, 27, and 36 leaves a remainder 5 in each case is 113.

i hope this will help you!!❣❣❣

Answer 2

Answer:

N=677

Step-by-step explanation:

so, (N-5) has to be Lcm of 24,32 or 42

LCM (24,32,42) = 672 = (N-5)