Find the least number which when divided by 20,25 and 30 leaves a remainder 7 in each case.
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Answer:
The numbers will be 27, 32 and 37
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Step-by-step explanation:
2|20,30,40
2|10,15,20
2|5,15,5
|1,3,1 least common multiple of 20,30,40is 120.
remainder is given as 7. so answer 120+7=127
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