Math, asked by harmindersingh7355, 5 months ago

Find the least number which when divided by 30, 40 and 50 leaves
remainder 5 in each case.

Answers

Answered by pousalidolai59

2

Answer:

LCM(30,40,50)=600

so the required no. is =600+5=605.

Hence , 605 is the least number which when divided by 30, 40 and 50 leaves

remainder 5 in each case.

Answered by nehajha71

0

Answer:

605 is the answer

Step-by-step explanation:

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