Question

Find the least number which when divided by 32 and 40 leaves the same remainder 5 in each case​

Answer 1

Answer:

165

Step-by-step explanation:

we find the lowest common multiple of 32and 40 which is 160 and add 5

hence, we get the least numbe=165

I hope, it will help you

Answer 2

here is your answer Cutiee.

to find the HCF first subtract the remainder from the given number.

$32 - 5 = 27$

$40 - 5 = 35$

now we have to find there HCF of the given numbers .

when we find have we have 3 for 27 and 7 or 5 for 35 .

hope my answer helps you.