Question

Find the least number which when divided by 35,56 and 91 leaves remainder 7 in each case

Answer 1

the ans is 3647.. whole solu in pic

Answer 2

Answer:

The required number is 3647.

Step-by-step explanation:

To Find -

Least number which can be divided by 35, 56 and 91 is LCM of 35, 56 and 91.

Solution -

Prime factorization of 35 -

⇒ 35 = 5 × 7  

Prime factorization of 56 -

⇒ 56 = 2³ × 7  

Prime factorization of 91 -

⇒ 91 = 7 × 13

LCM -

⇒ 23 × 5 × 7 × 13

⇒ 3640.

∴ Least number which can be divided by 35, 56 and 91 is 3640.

So, It is given - Leaves remainder 7 in each case.

Therefore,

⇒ 3640 + 7 = 3647.

∴ The least number which when divided by 35,56 and 91 leaves remainder 7 in each case is 3647.