in a practical unit if the unit of mass becomes double and that of time becomes half then 8 joule will be equal to.....unit of work
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Answered by
9
Joule = kg * m² / s²
Where kg is kilogram, m is meter and s is second.
Let new units be newJoule, newKg and newS.
Then formula for newJoule would be newKg * m² / (newS)²
According to the question newKg = 2kg i.e. 1kg = 1/2 * newKg
newS = s/2 i.e. 1s = 2 * newS
So 8 Joule = 8 * kg * m² / s²
= 8 * ( 1 / 2 * newKg ) * m² / (2 * newS)²
= (8 * 1/2 * 1/4) * newKg * m² / (newS)²
= 1 * newKg * m² / (newS)²
= 1 newJoule
Where kg is kilogram, m is meter and s is second.
Let new units be newJoule, newKg and newS.
Then formula for newJoule would be newKg * m² / (newS)²
According to the question newKg = 2kg i.e. 1kg = 1/2 * newKg
newS = s/2 i.e. 1s = 2 * newS
So 8 Joule = 8 * kg * m² / s²
= 8 * ( 1 / 2 * newKg ) * m² / (2 * newS)²
= (8 * 1/2 * 1/4) * newKg * m² / (newS)²
= 1 * newKg * m² / (newS)²
= 1 newJoule
Answered by
9
8joules of work done can be expressed,as
work= 8 joules = 8kg m²/ s²
where normal units mass = kg
length= m
Time = second=s
let the new units be KG,M and S
According to question ,new mass is double that of initial value.
KG = 2kg
M= no change mentioned = so assume same = m
S= s/2
work =8 kg m/ s
=8 (KG/2)*M²/(2S)²
=8/8(KGM²/S²)
=1 Joule of work.
work= 8 joules = 8kg m²/ s²
where normal units mass = kg
length= m
Time = second=s
let the new units be KG,M and S
According to question ,new mass is double that of initial value.
KG = 2kg
M= no change mentioned = so assume same = m
S= s/2
work =8 kg m/ s
=8 (KG/2)*M²/(2S)²
=8/8(KGM²/S²)
=1 Joule of work.
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