Question

find the least number which when divided by 40 50 and 60 leaves remainder 5 in each case​

Answer 1

The required number =LCM(40,50,60)+5

=10×4×3×5=600+5=605

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Answer 2

Answer:

40-5 = 35

50-5 = 45

60-5 = 55

Now HCF od 35,45 and 55 is

35 = 5*7

45 = 3*3*5

55 = 5*11

HCF(35,45,55) = 5

Therefore,

The least number which when divided by 40, 50 and 60 leaves remainder 5 in each case​ is 5.

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