Question

Find the least number which when divided by 5, 7 and 13 leaves the same remainder 3 in each case 398 453 458 463

Answer 1

Answer:

The answer for given numbers is 458. 458 also the least number which gives 3 reminder when divided with 5, 7 or 13.

Step-by-step explanation:

To know the least number which can be divided with 5, 7 and 13.

We need to find the LCM of 5, 7 and 13 first.

Since all 3 are prime numbers

LCM of 5, 7 and 13 = 5 x 7 x 13 = 455.

To get 3 reminder, we need to add 3 to above LCM.

Hence the number is 455 + 3 = 458.

So 458 is the least number when divided with 5, 7 and 13 leaves a reminder of 3.

Answer 2

Answer:

458

Step-by-step explanation:

Find the least number which when divided by 5, 7 and 13 leaves the same remainder 3 in each case 398 453 458 463

to find this we need to find LCM of

5 , 7 & 13

as there is no common factor in 5 , 7 & 13

so LCM = 5 * 7 * 13 = 455

Let say number = x is the least number for which remainder = 3 when divided by 455

(x-3)/455 = 1

=> x -3 = 455

=> x = 458