Find the least number which when divided by 5 and 9 will leave remainders of 3 and 7 respectively. A. 47 b. 88 c. 43 d. 92
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Step-by-step explanation:
Answer c is right:
In this question you just the least options
That is 43
Now checking the divisibility of each number
43-3=40 is divided by 5; Correct
43-7=36 is divided by 9: This is also correct
So the option 3 is right
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