Math, asked by sudheer28, 1 year ago

Find the least number which when divided by 6,10,15,30 leaves a remainder 3 in each case

Answers

Answered by BrainlyPrincess
26
Here is your answer⬇️⬇️

First we will find the LCM of 6, 10, 15, 30

6 = 2 × 3

10 = 2 × 5

15 = 3 × 5

30 = 3 × 2 × 5

LCM = 30

Now,

30 + 3 = 33

So, the least number is 33.

sudheer28: answer is 63
Answered by Anonymous
2
\textbf{Your answer } !!

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\text{Prime factorisation of the given numbers} ⬇⬇

 6 = 2 ( 3 ) \\ \\ 10 = 2 ( 5 ) \\ \\ 15 = 3 ( 5 ) \\ \\ 30 = ( 2 ) ( 3 ) ( 5 ) \\ \\ L . C . M = 2 ( 3 ) ( 5 ) \\ \\ L . C . M = 30 \\ \\ According \:to \:the \:question \\ \\ Remainder = 3 \\ \\ 30 + 3 = 33 \\ \\ Hence \:least \:number \:is\: 33

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