Question

Find the least number which when divided by 6. 15 and 18 leave remainder
5 in each case.​

Answer 1

Answer:

9000 can be the correct answer dude

Answer 2

Solution :-

To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case,

we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number. L.C.M. of 6, 5 and 18

6 = 2*3

15 = 3*5

18 = 2*3*3

L.C.M. of 6, 15 and 18 = 2*3*3*5 = 90

Now, 5 + 90 = 95

Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.

Let us check our answer.

1) 95/6 Quotient = 15 Remainder = 5

2) 95/15 Quotient = 6 Remainder = 5

3) 95/18 Quotient = 5 Remainder = 5 So, the required number is 95. Answer.

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