Math, asked by vanshjaat99, 11 months ago

find the zeroes of polynamial 5√5x^2+30x+8√5​

Answers

Answered by manjusharma143pc6zqk
2

Answer:

so easy

Step-by-step explanation:

5√5x2+20x+10x+8√5

5x(√5+4)+2√5(√5x+4)

x=-2√5/5 , x=-4/√5

Answered by ayushyadav143
0

Answer:

5√5x² + 30x + 8√5

splitting the middle term

= 5√5x² + 20x + 10x + 8√5

= 5√5x² + 4 × 5x + (2√5 ) × √5 x + 2√5 × 4

= 5x ( √5x + 4 ) + ( 2√5 ) [ √5x + 4 ]

= ( √5x + 4 ) ( 5x + 2√5 )

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