find the zeroes of polynamial 5√5x^2+30x+8√5
Answers
Answered by
2
Answer:
so easy
Step-by-step explanation:
5√5x2+20x+10x+8√5
5x(√5+4)+2√5(√5x+4)
x=-2√5/5 , x=-4/√5
Answered by
0
Answer:
5√5x² + 30x + 8√5
splitting the middle term
= 5√5x² + 20x + 10x + 8√5
= 5√5x² + 4 × 5x + (2√5 ) × √5 x + 2√5 × 4
= 5x ( √5x + 4 ) + ( 2√5 ) [ √5x + 4 ]
= ( √5x + 4 ) ( 5x + 2√5 )
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