find the least number which when divided by 6,15 and 18 leaves a remainder 5 in each case
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Answered by
12
Answer:
L.C.M. of 6, 5 and 18
6 = 2*3
15 = 3*5
18 = 2*3*3
L.C.M. of 6, 15 and 18 = 2*3*3*5 = 90
Now, 5 + 90 = 95
Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.
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Step-by-step explanation:
Answered by
4
Answer:
95
Step-by-step explanation:
first we find the LCM
LCM of 6,15,18 = 90
now add 5 to the LCM
90+5=95
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